j^2+3j-18=0

Solution for j^2+3j-18=0 equation:

Simplifying
j2 + 3j + -18 = 0

Reorder the terms:
-18 + 3j + j2 = 0

Solving
-18 + 3j + j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-6 + -1j)(3 + -1j) = 0

Subproblem 1
Set the factor '(-6 + -1j)' equal to zero and attempt to solve:

Simplifying
-6 + -1j = 0

Solving
-6 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + -1j = 0 + 6

Combine like terms: -6 + 6 = 0
0 + -1j = 0 + 6
-1j = 0 + 6

Combine like terms: 0 + 6 = 6
-1j = 6

Divide each side by '-1'.
j = -6

Simplifying
j = -6
Subproblem 2
Set the factor '(3 + -1j)' equal to zero and attempt to solve:

Simplifying
3 + -1j = 0

Solving
3 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1j = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1j = 0 + -3
-1j = 0 + -3

Combine like terms: 0 + -3 = -3
-1j = -3

Divide each side by '-1'.
j = 3

Simplifying
j = 3
Solution
j = {-6, 3}